Question

On aplication of a constant torque a wheel is turn from rod through 400rad in 10s . Find alpha if same torque and what will the angular velocity pf the wheel after 20sec from the start

Answer 1

Answer:

$\alpha =8\ \frac{rad}{s^2}$

$\omega _f=160 rad/s$

Explanation:

Given that

$\omega _i=0$

The wheel turn 400 rad in 10 sec

here given that torque is constant so we can apply motion equation

As we know that

$\omega _f=\omega _i+\alpha t$

$\omega _f=10\alpha$   at t= 10 s

$\omega _f^2=\omega _i^2+2\alpha \theta$

So

$100\alpha ^2=2\alpha \times 400$

$\alpha =8\ \frac{rad}{s^2}$

Now final velocity at t= 20 s

$\omega _f=\alpha t$

$\omega _f=20\times 8$

$\omega _f=160 rad/s$