Question

on being heated in oxygen 5.72 g of red metallic oxide A was converted to 6.36 gram black metallic oxide B When 4.77 g of B was heated in a stream of H2 gas, 3.81g of metal M was formed ( Given, atomic weight of metal is 63.50)... 1)the formula of red metallic oxide A is (1) MO (2)MO2 (3) M2O (4) M2O3 with explanation ​

Answer 1

Answer:

Weight of metal obtained on heating 4.77g of oxide B =3.81g

Weight of oxygen lost = weight of oxide - weight of metal =4.77g−3.81g

=0.96g

Equivalent weight of metal in oxide B=( weight of metal/ weight of oxygen lost )×8 =(3.81/0.96)×8

=31.75

Answer 2

Explanation:

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