Question

On dividing 2x³-5x²+1 by g(x), if remainder is 17x-6 and quotient is 2x-7 , find g(x)​

Answer 1

Answer:

$= > 2 {x}^{3} - 5 {x}^{2} + 1 = g(x) \times (2x - 7) + (17x - 6)$

$= > g(x) = \frac{2 {x}^{3} - 5 {x}^{2} + 1 - 17x + 6 }{2x - 7}$

$= > g(x) = \frac{2 {x}^{3} - 5 {x}^{2} - 17x + 7 }{2x - 7}$