Question

on dividing 3 x cube minus 2 x square+ 5 x + 5 by polynomial p (x) the quotient and remainder are x square minus x + 2 and -7 find the p( x)​

Answer 1

Answer:

Step-by-step explanation:

Follow the pic and get u r answer please mark as brainlyest

Answer 2

Answer:

• Dividend : 3x³ – 2x² + 5x + 5
• Divisor : p(x)
• Quotient : x² – x + 2
• Remainder : – 7

$\underline{\bigstar\:\textsf{According to the Question Now :}}$

$\dashrightarrow\tt\:\:Dividend = Divisor\times Quotient + Remainder\\\\\\\dashrightarrow\tt\:\:3x^3-2x^2+5x+5 = \lbrack p(x)\times(x^2-x + 2)\rbrack-7\\\\\\\dashrightarrow\tt\:\:3x^3-2x^2+5x+5-7= p(x)\times(x^2-x+2)\\\\\\\dashrightarrow\tt\:\:3x^3-2x^2+5x+2= p(x)\times(x^2-x+ 2)\\\\\\\dashrightarrow\tt\:\:p(x) = \dfrac{3x^3-2x^2+5x+2}{x^2 - x + 2}\\\\\\\dashrightarrow\:\:\underline{\boxed{\red{\tt p(x) = 3x + 1}}}$

⠀

$\therefore\:\underline{\textsf{Value of p(x) will be \textbf{(3x + 1).}}}$

$\rule{120}{1}$

$\boxed{\begin{array}{l | c | r}(\sf x^2-x+2) &\sf3x^3-2x^2+5x+2\:\:\qquad&\sf3x+1\\ &\sf3x^3-3x^2+6x\:\qquad\qquad\\ & ( - )\quad( + )\quad( - )\qquad\qquad\\&\rule{90}{0.8}\quad\:\:\:\\&\sf\:\:x^2-x+2\\ &\sf\:x^2-x+2\\ & (-)\:\:(+ )\:\:(-)\\&\quad\rule{85}{0.8}\\&\qquad\qquad\sf0\end{array}}$