On dividing 3x2-x3-3x+5 by a polynomial g(x),the quotient and remainder were x-2 and 3 respectively.find the polynomial g(x).
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Answered by
21
Answer:
g(x) = -x² + x - 1
Step-by-step explanation:
Hi,
Given the quotient , q(x) = (x-2)
remainder, r(x) = 3
polynomial p(x) = -x³ + 3x² - 3x + 5
But we now, by using Euclid's algorithm
p(x) = g(x)*q(x) + r(x).
Since q(x) is of degree 1, g(x) should be a polynomial of degree 2 since
the given polynomial is of degree 3.
Let g(x) be of form ax² + bx + c, now we know that
p(x) = -x³ + 3x² - 3x + 5 = (ax² + bx + c)(x-2) + 3
= ax³ +(-2a + b) x² + (-2b + c)x + 3 -2c
Now comparing the coefficient of x³ on both sides, we get
a = -1
Comparing the coefficient of x², we get
-2a + b = 3
=> 2 + b = 3
=> b = 1
Comparing the coefficient of x, we get
-2b + c = -3
=> -2 + c = -3
=> c = -1
Thus g(x) = -x² + x - 1.
Hope, it helped !
Answered by
6
Answer:
g(x)= x^2-x+1
Step-by-step explanation:
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