Question

On dividing a positive integer m by 9 we get 7 as a remainder. If 3m-1 is dividing by 9

Answer 1

Answer:

Let Q be the quotient

we know that dividend-: divisor× quotient + remainder

9Q+7= m

put value

3(9 Q+7) -1

=27 Q+ 21-1

=27Q+20

we can write 20 as 18 + 2

27Q+18+2

taking 3 as common

(3(9Q+6)+2)÷9

2 should be remainder

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hope it will be helpful

Answer 2

Answer:

When the positive integer n, is divided by 9, let the quotient be q.

⇒n=9q+7.

⇒3n=3(9q+7)=27q+21.

⇒3n−1=27q+21−1=27q+20=9(3q+2)+2.

⇒ Dividing 3n−1 by 9 is equivalent to dividing 9(3q+2)+2 by 9.

Since 9 is a factor of 9(3q+2) and 2<9, the remainder when 9(3q+2)+2 is divided by 9 is 2.

⇒ The remainder when 3n−1 is divided by 9 is 2.

Explanation:

I hope it is hlp full for you........