On dividing a positive integer n by 9, we get 7 as a remainder. What will be the remainder if (3n-1) is divided by 9?
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We know that dividing a positive integer n by 9, we get 7 as a remainder.
n/9=7
n=7x9
n=63
so =(3x36-1)/9
=3x7-1
=21-1
=20
We know that dividing a positive integer n by 9, we get 7 as a remainder.
n/9=7
n=7x9
n=63
so =(3x36-1)/9
=3x7-1
=21-1
=20
Warzone:
everything in the book is not suppose to be correct
maybe
lemme see
okay.
Look at the work i have shown. You may understand why the answer is 20
yeah....but where is quotient?
n=9q+7
the answer is 2
i got it
i solved it
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