on dividing a positive integer n by 9 we get 7 as remainder. what will be the remainder if ( 3n-1) 3 is divisible by 9?
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Given A positive integer n is divided by 9 gives 7 as the remainder.
Let a be quotient
n = 9a+7
3n-1 is divided by 9
now, 3n-1= 3(9a+7)-1
=27a + 21-1
=27a +20 = 27 a + 18 + 2
= 9( 3a + 6) + 2 when divided by 9
Remainder = 2.
Let a be quotient
n = 9a+7
3n-1 is divided by 9
now, 3n-1= 3(9a+7)-1
=27a + 21-1
=27a +20 = 27 a + 18 + 2
= 9( 3a + 6) + 2 when divided by 9
Remainder = 2.
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