On dividing x^3-3x^2+x+2 by polynomial g(x), the quatient and the remainder were x-2 and -2x+4, respectively find g(x)
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Answer:
•g(x)= x^2-x+1
Step-by-step explanation:
It is given that
p(x) = x^3-3x^2+x+2
g(x) = ?
q(x) = x-2
r(x) = -2x+4
~By Division Algorithm
g(x)×q(x)+r(x)=p(x)
g(x)×(x-2)+(-2x+4) = x^3-3x^2+x+2
g(x)×(x-2)= x^3-3x^2+x+2+2x-4
g(x)×(x-2)= x^3-3x^2+3x-2
____see the picture____
~The answer had been solved.....
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