Question

on dividing x^3-3x^2+x+2 by polynomial g(x), the quotient and remainder were x-2 and 4-2x respectively then find g(x).

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Answer 1

Answer:

We know that

Dividend= quotient*divisor+remainder                      (1)

Given,

Dividend =  x³ – 3x² + x + 2

Divisor = polynomial g(x),

the quotient and remainder were x – 2 and – 2x + 4, respectively.

Put this in equation(1)

x³ – 3x² + x + 2 =(x-2)*g(x)+(-2x+4)

x³ – 3x² + x + 2+2x-4 = (x-2)*g(x)

x³ – 3x²+3x-2 = (x-2)*g(x)

(x-2)( x²-x+1 )= (x-2)*g(x)

Hence, g(x)= ( x²-x+1 )

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Answer 2

Answer

THIS  QUESTION IS GIVEN IN  NCERT EXEMPLAR YOU CAN GET THERE

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