Question

On E.coli chromosome,opposite to Ori C there is a sequence where replication
is terminated is known as

Options
O promotor
O Ter sequence
Operator
OriT

send me correct option​

Answer 1

Answer:

Given

a

2

=13 and a

5

=25

We know that

a

n

=a+(n−1)d

∴a

2

=a+(2−1)d

⇒13=a+(2−1)d

⇒a+d=13 ...(i)

and a

5

=a+(5−1)d

⇒25=a+4d

⇒a+4d=25 ...(ii)

Now, subtracting (i) from (ii), we get

3d=12

⇒d=4

Now a+d=13 [from (i)]

⇒a=9

Hence, a

7

=a+6d=9+6(4)

⇒a

7

=33

Answer 2

Answer:

The answer is O Ter sequence

Explanation:

The O Ter sequence is present opposite to Ori C on the E. coli chromosome. The ter sequence is the termination sequence of the E.coli chromosome replication. The terminator protein (tus) of the Escherichia coli replication binds to the ter sequence. It actually blocks the replication fork that is coming from one side. In this, the tus-ter mechanism is sensitive to the DNA motor translocation polarity. Helicase enzyme immediately unpairs a pair GC (6) on the E. coli chromosome and traps the G (6) to aid lock-formation so that polymerase does not bind to C (6) and prevent lock formation.

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