Math, asked by llMishtill, 5 months ago

On increasing the radius of a sphere by 10% find the percentage increase in its volume​

Answers

Answered by llAloneSameerll
15

\huge\r</strong><strong>m</strong><strong>\underline{\underline{\pink{Question:-}}}

On increasing the radius of a sphere by 10%, find the percentage of increase in its volume .

\huge\rm\underline{\underline{</strong><strong>\</strong><strong>green</strong><strong>{Solution:-}}}

33.1 %

\huge\r</strong><strong>m</strong><strong>\</strong><strong>underline{\underline</strong><strong>{</strong><strong>\</strong><strong>b</strong><strong>l</strong><strong>u</strong><strong>e</strong><strong>{</strong><strong>Solu</strong><strong>tion:-}}}

Let the original radius of the sphere be r units

Then, its original volume = (4/3 × π )

Radius of the new sphere = (110% of r) units

= (110/100 × r) units

= (11/10 × r) units

Volume of the new sphere = (4/3 π × 11 r/10) cubic units

= (4/3πr ³ × 1331/1000) cubic units

Increase in sphere's volume = {(4/3πr³×1331/10004/3πr³)} cubic units

= {(4/3πr³×1331/10001)} cubic units

= {4/3πr³×(13311000/1000)} cubic units

= {4/3πr³×331/1000} cubic units

Percentage increase in its volume = (4/3πr³×331/10000×100/4/3πr³)%

= (331×100/1000)%

= 33.1%

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