Question

On January 1st, 2010 the average age of 11 members of a cricket
team was 30 years. After four years, a player X from the team was
replaced by another player Y. After one more year, player Y was
replaced by another player Z, as a result of which the average age of
24
34 –
the team then became 11 years. If the age of player Y is 4 years
less than that of player X, then the age of player Z is how many years
more/less than that of player Y?​

Answer 1

JAN 1ST 2010,

sum of ages of 11 players be X

X÷11=30

after 4 years

X is replaced with Y

X-4=Y

after 1 year

Y is replaced with Z

Y-1=Z

the answer is the age of player Z is 1 year less then that of player Y

Answer 2

Given:

On January 1st, 2010 the average age of 11 members of a cricket

team was 30 years. After four years, a player X from the team was

replaced by another player Y. After one more year, player Y was

replaced by another player Z, as a result of which the average age of 24.

To prove:

The age of player Z is how many years more/less than that of player Y?

Solution:

We know that a team of cricket has 11 players.  

So, According to question,  

On January 1st 2010,

We will assume that sum of ages of 11 players be X years.  

Then the first statement depicts the following formula:

X÷11=30

After 4 years,  

If X is replaced with Y, then we can say that:

X-4=Y

Then After 1 year,  

If Y is replaced with Z, then we can say that:

Y-1=Z

Hence, Age of player Z is 1 year less than that of Age of player Y.  

So, the answer is that age of player Z is 1 year less than that of player Y.