Question

on passing electricity through dil. H2so4 solution the amount if substance liberated at the cathide and anode are in the ratio?

Answer 1

Answer:

The answer is 8:1

Explanation: I cannot give exact and most appropriate explanation but when you pass electricity through dilute H₂SO₄ Solution,

At cathode: Hydrogen is liberated

At anode: Oxygen is liberated

The equivalent weight of Hydrogen is 1 and that of Oxygen is 8 and there's also some direct relation (I've less knowledge in Electro chemistry sorry)

So that's why the amount deposited is 1:8

Have a nice day :)

Answer 2

Explanation:

here is best of all the answer