Question

On rationalising the denominator of 1/root5 + root2, we get..?​

Answer 1

Answer:

=35−2

Step-by-step explanation:

\begin{gathered} Rationalising\: the \: \\denominator \: of \: \frac{1}{\sqrt{5}+\sqrt{2}}\end{gathered}Rationalisingthedenominatorof5+21

Multiply numerator and denominator by (√5-√2), we get

=\frac{\sqrt{5}-\sqrt{2}}{(\sqrt{5}+\sqrt{2})(\sqrt{5}-\sqrt{2})}(5+2)(5−2)5−2

=\frac{\sqrt{5}-\sqrt{2}}{(\sqrt{5})^{2}-(\sqrt{2})^{2}}(5)2−(2)25−2

/* By algebraic identity:

(a+b)(a-b)=a²-b²*/

=\frac{\sqrt{5}-\sqrt{2}}{5-2}5−25−2

=\frac{\sqrt{5}-\sqrt{2}}{3}35−2

/* Denominator rationalised */

Therefore,

\frac{1}{\sqrt{5}+\sqrt{2}}=\frac{\sqrt{5}-\sqrt{2}}{3}5+21=35−2

Answer 2

Answer:

Ans=(√5-√2)/3

Hope it helps you.

Step-by-step explanation:

Pls mark as brainliest