Question

On rationalizing √7/ √3+√2 we get​

Answer 1

Answer:

$\mathrm{Simplify}\:\frac{\sqrt{7}}{\sqrt{3+\sqrt{2}}}:\quad \sqrt{3-\sqrt{2}}\quad \left(\mathrm{Decimal:\quad }\:1.25928\dots \right)$

Step-by-step explanation:

$\frac{\sqrt{7}}{\sqrt{3+\sqrt{2}}}$

$\mathrm{Apply\:radical\:rule}:\quad \frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}$

$\frac{\sqrt{7}}{\sqrt{3+\sqrt{2}}}=\sqrt{\frac{7}{3+\sqrt{2}}}$

$=\sqrt{\frac{7}{3+\sqrt{2}}}$

$=\sqrt{3-\sqrt{2}}$