Question

what would be the final temperature of
of mixture
if 40 grams of water at 20 degrees celsius mixed with 60 grams of
of water at 30 degrees Celsius

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Answer 1

Answer:

since it is given that 40 gms water at 20 ⁰ C and 40 gms of water at 40⁰ C are mixed. Since the masses of the liquid at different temperatures are same, the answer is very easy and simple : average of 20⁰C and 40⁰C. that is: 30⁰C.

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final temperature of the mixture =

= [ m1 * T1 + m2 * T2 ] / (m1 + m2)

= [ 40 gms * 20⁰ C + 40 gms * 40⁰C ] / (40+40)

= 800 / 100 = 80⁰C

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another way using specific heats :

let the final temperature be = T ⁰C

Amount of heat given out by the hot water = m * s * (40⁰C - T)

= 50 gms * s* (40 -T)

Amount of heat taken in by the cold water = m * s * (T - 20⁰C)

= 50 gms * s * (T - 20 )

As the amounts are equal, because the heat is transferred from hotwater to the cold water without any loss of heat to any surroundings,

50 * s * (40 -T) = 50 gm * s * (T-20)

40 - T = T - 20

2 T = 60 => T = 30⁰C