Question

On rationalizing the denominator of 1/√7-2 we get what ?​

Answer 1

$Rationalising \: \frac{1}{\sqrt{7} - 2} \\= \frac{1}{\sqrt{7} - 2}\times \frac{(\sqrt{7} + 2)}{(\sqrt{7}+2)}$

$= \frac{(\sqrt{7}+2)}{(\sqrt{7})^{2} - 2^{2})}\\= \frac{(\sqrt{7}+2)}{(7 - 4)}\\= \frac{(\sqrt{7}+2)}{3}$

Therefore.,

$\red {\frac{1}{\sqrt{7} - 2}}\green { =\frac{(\sqrt{7}+2)}{3}}$

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Answer 2

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