Physics, asked by beastbroappy, 7 hours ago

On seeing a board of speed limit, a car decreases its speed from 90 km/h to 72 km/h at constant acceleration in 4 s. The acceleration of the car is
a) 1.25m/s2
b)-1.25m/s2
c)2.5m/s2
d)-2.5m/s2

Answers

Answered by VishalSharma01
94

Answer:

Explanation:

Given,

Initial velocity of the car, u = 90 km/h = 90 × 5/18 = 25 m/s

Final velocity of the car, v = 72 km/h = 72 × 5/18 = 20 m/s

Time taken by the car, t = 4 seconds

To Find,

Acceleration by the car, a

Formula to be used,

1st equation of the motion,

v = u + at

Solution,

Putting all the values, we get

v = u + at

⇒ 20 = 25 + a × 4

⇒ 20 - 25 = 4a

⇒ - 5 = 4a

⇒ - 5/4 = a

a = - 1.25 m/s².

Hence, the acceleration of the car is - 1.25 m/s².

Here, Option b, - 1.25 m/s² is correct answer.

Answered by MяMαgıcıαη
111

\large\underline{\sf{Given}}

\:

» Initial velocity (u) of car = 90 km/h.

» Initial velocity (u) in m/s = 90 × 5/18 = 25 m/s.

» Final velocity (v) of car = 72 km/h.

» Final velocity (v) in m/s = 72 × 5/18 = 20 m/s.

» Time taken (t) by car to decrease it's speed = 4 s.

\:

\large\underline{\sf{To\:Find}}

\:

» Acceleration of car?

\:

\large\underline{\sf{Solution}}

\:

\underbrace{\underline{\sf{\bigstar\:Understanding\:the\:Question\:::}}}

\:

Here, we are given that on seeing a board of speed limit, a car decreases its speed from 90 km/h to 72 km/h at constant acceleration in 4 s. Henc, we have initial velocity, final velocity and time taken. We have to find the acceleration of car. We can easily find it by using first equation of motion :: v = u + at. In which, 'v' is final velocity, 'u' is initial velocity, 'a' is the acceleration and 't' is time taken. So, let's solve it!

\:

\sf \longrightarrow\: v = u + at

\:

Putting all known values,

\:

\sf \longrightarrow\: 20 = 25 + a\big(4\big)

\\ \sf \longrightarrow\: 4a = 20 - 25

\\ \sf \longrightarrow\: 4a = -5

\\ \sf \longrightarrow\: a = {\cancel{\dfrac{-5}{4}}}

\\ \sf \longrightarrow\: \pink{Acceleration\:\big(a\big)\:of\:car = -1.25\:m/s^2}

\:

\therefore\:{\underline{\bf{Option\:\big(b\big)\:-1.25\:m/s^2\:\sf{is\:correct!}}}}

\:

\large\underline{\sf{More\:to\:know}}

\:

Three equations of motion,

\:

  • v = u + at [Used above]

  • s = ut + ½ at²

  • = + 2as

\:

Some important definitions,

\:

  • Acceleration

Acceleration is the process where velocity changes. Since, velocity is the speed and it has some direction. So, change of velocity us considered as acceleration.

\:

  • Initial velocity

Initial velocity is the velocity of the object before the effect of acceleration.

\:

  • Final velocity

After the effect of acceleration, the velocity of the object changes, the new velocity gained by the object is known as final velocity.

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