On seeing a board of speed limit, a car decreases its speed from 90 km/h to 72 km/h at constant acceleration in 4 s. The acceleration of the car is
a) 1.25m/s2
b)-1.25m/s2
c)2.5m/s2
d)-2.5m/s2
Answers
Answer:
Explanation:
Given,
Initial velocity of the car, u = 90 km/h = 90 × 5/18 = 25 m/s
Final velocity of the car, v = 72 km/h = 72 × 5/18 = 20 m/s
Time taken by the car, t = 4 seconds
To Find,
Acceleration by the car, a
Formula to be used,
1st equation of the motion,
v = u + at
Solution,
Putting all the values, we get
v = u + at
⇒ 20 = 25 + a × 4
⇒ 20 - 25 = 4a
⇒ - 5 = 4a
⇒ - 5/4 = a
⇒ a = - 1.25 m/s².
Hence, the acceleration of the car is - 1.25 m/s².
Here, Option b, - 1.25 m/s² is correct answer.
» Initial velocity (u) of car = 90 km/h.
» Initial velocity (u) in m/s = 90 × 5/18 = 25 m/s.
» Final velocity (v) of car = 72 km/h.
» Final velocity (v) in m/s = 72 × 5/18 = 20 m/s.
» Time taken (t) by car to decrease it's speed = 4 s.
» Acceleration of car?
Here, we are given that on seeing a board of speed limit, a car decreases its speed from 90 km/h to 72 km/h at constant acceleration in 4 s. Henc, we have initial velocity, final velocity and time taken. We have to find the acceleration of car. We can easily find it by using first equation of motion :: v = u + at. In which, 'v' is final velocity, 'u' is initial velocity, 'a' is the acceleration and 't' is time taken. So, let's solve it!
Putting all known values,
Three equations of motion,
- v = u + at ㅤㅤㅤㅤ[Used above]
- s = ut + ½ at²
- v² = u² + 2as
Some important definitions,
- Acceleration
Acceleration is the process where velocity changes. Since, velocity is the speed and it has some direction. So, change of velocity us considered as acceleration.
- Initial velocity
Initial velocity is the velocity of the object before the effect of acceleration.
- Final velocity
After the effect of acceleration, the velocity of the object changes, the new velocity gained by the object is known as final velocity.
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