Question

On selling two cameras for 500 each, a person made no loss or gain. If he had sold one
camera at 25% gain, then at what loss per cent did he sell the other camera?
(Hint: CP of 2 cameras = SP of 2 cameras = *(5000 * 2)]​

Answer 1

Answer:

I can try pls wait for 2 minutes

Step-by-step explanation:

first camera at 25% gain

500×25\100=125

500+125=625

therefore price of first camera equals to 625

hence second camera equals to 1000 - 625 equals to 375

Hope it helps

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Answer 2

Loss% on other camera=16.67%

Step-by-step explanation:

S.P of each camera=Rs 500

Total S.P of two cameras=500+500=Rs 1000

Let x be the C.P of one camera and y be the C.P of other camera

When a person made no loss or gain

Then, total S.P=Total C.P

C.P of two cameras=S.P of two cameras=Rs 1000

Profit on one camera=25 %

Therefore, profit=$\frac{25}{100}x$

C.P=S.P-profit

$x=500-\frac{25}{100}x$

$500=x+\frac{25}{100}x$

$500=\frac{100x+25x}{100}$

$500=\frac{125}{100}x$

$x=\frac{500\times 100}{125}=400$

C.P of one camera on which profit 25%=Rs 400

C.P of other camera=y=Total C.P of two cameras-C.P of one camera on which 25% profit=1000-400=Rs 600

C.P>S.P

Therefore, loss on other camera=C.P-S.P=600-500=Rs 100

Loss% on other camera=$\frac{loss}{C.P}\times 100$

Loss% on other camera=$\frac{100}{600}\times 100=16.67%$

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