Question

On sellling a tea at 5% loss and a lemon set at 15% gain,a crockery seller gains Rs.7.If he sells the tea set at 5% gain and the lemon set at 10% gain,he gains Rs.13.Find the actual price of the tea set and the lemon set

Answer 1

Step-by-step explanation:

let the cost of tea set be Rs'x' and

the cost of lemon set be Rs'y'.

the shopkeeper sells a tea set at 5%loss and a lemon set at 15% gain

so the loss on tea set=X*5/100

and the gain on lemon set=y*15/100

total gain=15y/100-5x/100=70

15y-5x=7000

dividing it by 5,we get

3y-x=1400

-x+3y=1400.......(1)

if he sells the tea set at 5%gain

and lemon set at 10%gain,he gains Rs130.

therefore,

5x/100+10y/100=130

5x+10y=13000

dividing it by 5,we get

X+2y=2600.........(2)

adding (1)and (2),we get

-X+3y=1400

X+2y=2600

___________

5y=4000

___________

y=4000/5

y=800

substituting the value of y=800 in (2),

we get

X+2y=2600

X+2*800=2600

x=2600-1600

X=1000

so the cost price of tea set is Rs800

Answer 2

Step-by-step explanation:

Let the cost of tea set be Rs 'x' and the cost of lemon set be Rs 'y'.

The shopkeeper sells a tea set at 5 % loss and a lemon set ate 15 % gain.

So, the loss on tea set = x*5/100

And the gain on lemon set = y*15/100

Total gain = 15y/100 - 5x/100 = 70

15y - 5x = 7000

Dividing it by 5, we get

3y - x = 1400

-x + 3y = 1400...........(1)

If he sells the tea set at 5 % gain and lemon set at 10 % gain, he gains Rs 130.

Therefore,

5x/100 + 10y/100 = 130

5x + 10y = 13000

Dividing it by 5, we get

x + 2y = 2600 ..............(2)

Adding (1) and (2), we get

- x + 3y = 1400

x + 2y = 2600

______________

5y = 4000

______________

y = 4000/5

y = 800

Substituting the value of y = 800 in (2), we get

x + 2y = 2600

x + 2*800 = 2600

x + 2600 - 1600

x = 1000

So the cost price of tea set is Rs 1000 and the cost price of lemon set is Rs 800.