Question

On sided ab ,bc and ac of a triangle abc , equilateral triangles abd , bce, caf are drawn . Prove that ae=bf=cd

Answer 1

Prove ΔABE≅ ΔDBC using SAS congruence theorem (Just ask if uh don't figure it yourself on how to do it)
so that AE = CD
Similarly, prove
ΔABF≅ ΔADC to get CD = BF
Combining above two equations we get
AE = BF = CD

Hope This Helps :)