Question

On simplification of [(-5) + 8] ÷ (4 – 1), we get the result

Answer 1

We have,

$\quad \: [( - 5) + 8] \div (4 - 1) \\ \\ = [ - 5 + 8] \div (4 - 1) \\ \\ = [8 - 5] \div (4 - 1) \\ \\ = [3] \div (4 - 1) \\ \\ =[3] \div (3) \\ \\ = \frac{3}{3} = \frac{ \cancel{3} \: {}^{1} }{ \cancel{3} \: _1} \\ \\ = \bf 1$
..
..

Method Used :—

$\underline{ \boxed{ \bf \: BODMAS \: }}$

Answer 2

I don't nowyou only tell