On simplifying
2^x+3 × 3^2x-y ×5^x+y+3 × 6^y+1 / 6^x+1 × 10^y+3 × 15^x reduces to ?
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(c) 1 is correct Answer
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
3x+6y^3
Step-by-step explanation:
-First you add all the Xs
2x+x+x
-Then you multiply all the Ys
2y * 3y * y
* the Y has a 1 as an exponent by multiplying the Ys the exponents are added making the Y a Y^3
*the numbers are multiplied making it a 6
Together it forms 6y^3
-Ys and Xs cannot be added because they are different values so your answer would be 3x+ 6y^3=1
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similar sums
Solution for 15-x=2(x+3) equation:
Simplifying
15 + -1x = 2(x + 3)
Reorder the terms:
15 + -1x = 2(3 + x)
15 + -1x = (3 * 2 + x * 2)
15 + -1x = (6 + 2x)
Solving
15 + -1x = 6 + 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2x' to each side of the equation.
15 + -1x + -2x = 6 + 2x + -2x
Combine like terms: -1x + -2x = -3x
15 + -3x = 6 + 2x + -2x
Combine like terms: 2x + -2x = 0
15 + -3x = 6 + 0
15 + -3x = 6
Add '-15' to each side of the equation.
15 + -15 + -3x = 6 + -15
Combine like terms: 15 + -15 = 0
0 + -3x = 6 + -15
-3x = 6 + -15
Combine like terms: 6 + -15 = -9
-3x = -9
Divide each side by '-3'.
x = 3
Simplifying
x = 3
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