Math, asked by Aditiiiiiiiiiii, 8 months ago

On simplifying
2^x+3 × 3^2x-y ×5^x+y+3 × 6^y+1 / 6^x+1 × 10^y+3 × 15^x reduces to ?

Please Give Full Solution

(c) 1 is correct Answer​

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Answers

Answered by 123aishwarya123
3

Step-by-step explanation:

plz see the attachment

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Answered by PixleyPanda
0

Answer:

Step-by-step explanation:

3x+6y^3

Step-by-step explanation:

-First you add all the Xs

2x+x+x

-Then you multiply all the Ys

2y * 3y * y

* the Y has a 1 as an exponent by multiplying the Ys the exponents are added making the Y a Y^3

*the numbers are multiplied making it a 6

Together it forms 6y^3

-Ys and Xs cannot be added because they are different values so your answer would be 3x+ 6y^3=1

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similar sums

Solution for 15-x=2(x+3) equation:

Simplifying

15 + -1x = 2(x + 3)

Reorder the terms:

15 + -1x = 2(3 + x)

15 + -1x = (3 * 2 + x * 2)

15 + -1x = (6 + 2x)

Solving

15 + -1x = 6 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.

15 + -1x + -2x = 6 + 2x + -2x

Combine like terms: -1x + -2x = -3x

15 + -3x = 6 + 2x + -2x

Combine like terms: 2x + -2x = 0

15 + -3x = 6 + 0

15 + -3x = 6

Add '-15' to each side of the equation.

15 + -15 + -3x = 6 + -15

Combine like terms: 15 + -15 = 0

0 + -3x = 6 + -15

-3x = 6 + -15

Combine like terms: 6 + -15 = -9

-3x = -9

Divide each side by '-3'.

x = 3

Simplifying

x = 3

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