Question

a single electro specie in energy level orbit number n with energy x was provided with excess of energy it jumps to higher energy level with energy y it can emit radiations of 6 different wave length on deexcitement between these two energy level​

Answer 1

Answer:

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Answer 2

As shown in the above diagram, number of possible transitions/emitted wavelengths from (n+i)
th
energy level to n
th
level is given by:
=1+2+3..+i
=∑i
=
2
i(i+1)
​

Solving the above expression for six emitted wavelengths as:
6=
2
i(i+1)
​

i
2
+i−12=0
i=3
Therefore, E
X
​
=−R
H
​
(
n
2

Z
2

​
)andE
Y
​
=−R
H
​
[
(n+3)
2

Z
2

​
]
E
Y
​

E
X
​

​
=
Y
X
​
=
n
2

(n+3)
2

​

X/Y
​
=1+