Question

On simplifying (root5+root7)^2,we get

Answer 1

Answer:12+root35

Step-by-step explanation:(root5+root7)^2

(since (a+b)^2=a^2+b^2+2ab)

=(root5)^2+(root7)^2+2 (root5)×(root7)

=5+7+2 root35

=12+root35

Answer 2

Step-by-step explanation:

ANSWER:-

TO FIND:-

${( \sqrt{5} + \sqrt{7} )}^{2}$

Using Identity,

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$

${ (\sqrt{5}) }^{2} + {( \sqrt{7} )}^{2} + 2( \sqrt{5} \times \sqrt{7} )$

$5 + 7 + 2 \sqrt{35}$

On simplifying it, we get the result as

$12 + 2 \sqrt{35}$

is the answer.

Identities:-

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$

${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy$

${x}^{2} - {y}^{2} = (x + y)(x - y)$