Question

On starting with 1 mole of HI in a 2L container.Calculte the concentration of each species at equilibrium if Ko for the reaction is 16.​

Answer 1

Answer:

The concentration of each species at equilibrium if Ko for the reaction is 16 will be 4 and 6 respectively..!

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Answer 2

Answer:

the reaction, H

2

(g)+I

2

(g)⇌2HI(g), in a 2 litre flask 0.4 mole of each H

2

and I

2

are taken. At equilibrium 0.5 mol of HI are formed. The value of equilibrium constant K

c

will be 11.1.

0.5 moles of HI will be obtained from 0.25 moles of H

2

and 0.25 moles of I

2

.

0.4−0.25=0.15 moles of H

2

and 0.4−0.25=0.15 moles of I

2

will remain.

The equilibrium constant

K

c

=

[H

2

][I

2

]

[HI]

2

K

c

=

(

2 L

0.15 mol

)×(

2 L

0.15 mol

)

(

2 L

0.5 mol

)

2

K

c

=11.1