On subtracting (4ab + 9c – 4a^2) from (6a^2 + 5ab – 3c) we get *
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(6a²+5ab-3c) - (4ab+9c-4a²)
=6a²+5ab-3c-4ab-9c+4a²
=6a²+4a²+5ab-4ab-9c-3c
=10a²+ab-12c
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Answer:
aarush don't joke okay It is my school homework
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