On sum of numbers in GP..
Find 81-27+9+...-1/27.
Answers
Answered by
72
In the Given G.P
a=81 r=-1/3
So
[tex] (-1/3)^{n-1}=-(1/3)^7 [/tex]
So,n-1=7 ,n=8
So by![S_{n}=a(1-r^n)/1-r S_{n}=a(1-r^n)/1-r](https://tex.z-dn.net/?f=+S_%7Bn%7D%3Da%281-r%5En%29%2F1-r+)
We get![S_{8}=81(1-(-1/3)^8)/1-(-1/3) S_{8}=81(1-(-1/3)^8)/1-(-1/3)](https://tex.z-dn.net/?f=S_%7B8%7D%3D81%281-%28-1%2F3%29%5E8%29%2F1-%28-1%2F3%29+)
![S_{8}=1640/27 S_{8}=1640/27](https://tex.z-dn.net/?f=S_%7B8%7D%3D1640%2F27)
a=81 r=-1/3
So
[tex] (-1/3)^{n-1}=-(1/3)^7 [/tex]
So,n-1=7 ,n=8
So by
We get
Answered by
3
Answer:
pls mark me as brainlist
Attachments:
![](https://hi-static.z-dn.net/files/d10/bb71cd5c5690107f19f1789a1a9e2c3d.jpg)
Similar questions
English,
9 months ago
Computer Science,
9 months ago
English,
9 months ago
Computer Science,
1 year ago
English,
1 year ago
Math,
1 year ago