Question

On the basis of the following E° values, the strongest
oxidizing agent is :
[Fe(CN)₆]⁴⁻ → [Fe(CN)₆]³⁻ + e⁻ ; E° = – 0.35 V
Fe²⁺ → Fe³⁺ + e⁻; E° = – 0.77 V
(a) [Fe(CN)₆]⁴⁻ (b) Fe²⁺
(c) Fe³⁺ (d) [Fe(CN)₆]³⁻

Answer 1

The strongest oxidizing agent is :

• More positive the electrode potential, higher the oxidizing power. Hence more stronger oxidizing agent.

• We are given :

[Fe(CN)₆]⁴⁻ → [Fe(CN)₆]³⁻ + e⁻ ;

E° = –0.35 V

Fe²⁺ → Fe³⁺ + e⁻; E° = –0.77 V

• We can also conclude,

[Fe(CN)₆]³⁻ + e⁻ → [Fe(CN)₆]⁴⁻

E° = +0.35 V

Fe³⁺ + e⁻ → Fe²⁺

E° = +0.77V

• We can see that Fe³⁺ has the most positive electrode potential.

• Therefore, it is the strongest oxidizing agent among all above.

Answer 2

Hello Friend.!!

The answer of your question is..!!

Option. C

Thank you