Question

On the basis of the story that you have read ,how will you resolve a similar problem with your friend (describe the case) , if you had the special powers of a Sarpanch
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Answer 1

cos²A+sin²A=1

Therefore,

cos²A = 1-sin²A, i.e., cosA =

$\frac{ + }{} \sqrt{1 - sin {}^{2} \: a }$

This gives

cosA =

$\sqrt{1 - sin {}^{2} a}$

Hence,

tanA =

$\frac{sin \: a}{cos \: a} = \frac{sin \: a}{ \sqrt{1 - sin {}^{2} } \: a}$

, sec A =

$\frac{1}{cos \: a} = \frac{1}{ \sqrt{1 - sin {}^{2} } a}$