On the (Be's right angle, Des the midpoint of the Side
tc. if AB=6cm, Ber8cm, then the
length
of BD is
Answers
Answered by
1
Answer:
BD=6.2 cm
Step-by-step explanation:
In triangle ABC
Angle B=90 degree
AB=6 cm
BC=8 cm
D is the mid-point of AC.
In triangle ABC
AC^2=AB^2+BC^2AC
2
=AB
2
+BC
2
Using Pythagoras theorem
(hypotenuse)^2=(Base)^2+(perpendicular\;side)^2(hypotenuse)
2
=(Base)
2
+(perpendicularside)
2
AC^2=6^2+8^2AC
2
=6
2
+8
2
AC^2=36+64AC
2
=36+64
AC^2=100AC
2
=100
AC=\sqrt{100}=10 cmAC=
100
=10cm
AD=DC=\frac{1}{2}AC=\frac{1}{2}(10)=5 cm
2
1
AC=
2
1
(10)=5cm
We know that when a line is drawn from vertex and divide the opposite side into equal parts then, it will be perpendicular .
In right triangle DBC
BC^2=DB^2+DC^2BC
2
=DB
2
+DC
2
Substitute the values
8^2=DB^2+5^28
2
=DB
2
+5
2
64=DB^2+2564=DB
2
+25
DB^2=64-25=39DB
2
=64−25=39
DB=\sqrt{39}=6.2 cmDB=
39
=6.2cm
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