On the interval (0 , π/2)
the function log sin x is
(A) Increasing
(B) Decreasing
(C) Neither increasing nor decreasing
(D) None of these
correct answer is A
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Answer:
Increasing
Step-by-step explanation:
From (0,pi/2), sinx is(0,1) and for log it is (-infinite, 0)
So as for x= 0
f(x) = - infinite and for x=pi/2, f(x) = 0 so f is increasing
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