Question

On the level ground, the angle of elevations of a tower is 30° . On moving 20 m nearer, the angle of elevation is 60°. The height of the tower is

Answer 1

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Answer 2

Answer:

The height of the tower will be 10root 3 merters.

Step-by-step explanation:

letthe triangle be ABCD then angle B=90degree,angeBCA=60;

angle ACD 120;angle D=30 degree;

angle BAC=30 .

So, BC=x m;

AC=20 m bcoz angle ACD=angle ADC=30 degree;

therefore AC=CD=20m.

Let  AB-h m

then;

sin 60=h/20

therefore h=10root 3 meters.