Question

On the topic of imaginary numbers, how is -i^2 = -1?

Answer 1

Answer:

Imaginary numbers:

Imaginary numbers are the negative numbers inside the root.

• i is called as iota

The value of i is $\sqrt{-1}$

Since, i = $\sqrt{-1}$

On squaring both the sides

• i² = -1

Hence, the value of i² is -1.

_______________________________

Extra information:

Complex number:

Complex number is a number which contains real and imaginary part it is denoted by z.

• z = x + yi, where x and y are rational numbers.

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Answer 2

Answer:

$\huge\underline\mathcal\red{AnSWer}$

Imaginary numbers:

Imaginary numbers are the negative numbers inside the root.

i is called as iota

The value of i is $\sqrt{ - 1}$

Since, i = $\sqrt{ - 1}$

On squaring both the sides

i² = -1

Hence, the value of i² is -1.

_______________________________

Extra information:

Complex number:

Complex number is a number which contains real and imaginary part it is denoted by z.

z = x + yi, where x and y are rational numbers.