Question

Once 4 students from class IX F were selected for plantation of flower plants in the School garden. The selected students were Pankaj Raju Deepak and Renu. As shown PQ And MN are the parallel lines of
the plants. Pankaj planted a
sunflower plant at P and Raju
planted another sunflower at Q.    
Further Deepak was called to
plant any flowering plant at
point M he planted a Marigold
there now it was the turn of
Renu,she was told to plant a
flowering plant different from
the three planted one. So she
planted a rose plant at N.
There was a water pipe line XY
which intersect PQ and MN at
A and B and ∠ XBN = 60° ​

Answer 1

ANSWER;

i) According to the diagram,

60+z=180

z = 180 - 60

z = 120

ii)According to the diagram,

x = 60 ( corresponding  angles )

iii) we know that linear angle = 180 degree

  p + q = 180

iv) The corresponding angle to a is angle q

v) According to the diagram p+q = 180

( linear pair )

a+z =180  (linear pair )

thus, 180 + 180 = 360

according to the question,

360 degree / 6 = 60 degree

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Answer 2

Complete Question :- Refer to image .

Solution :-

given that,

• PQ || MN .
• XY is a transversal .
• ∠XBN = 60° .

so,

→ ∠z + ∠XBN = 180° (Angles on a straight line are supplementary.)

→ ∠z = 180° - 60°

→ ∠z = 120° (b) (Ans.)

now,

→ ∠x = ∠XBN (corresponding angles.)

→ ∠x = 60° (a) (Ans.)

and,

→ ∠p + ∠q = 180° (XB is a straight line , so angles are supplementary.) (c) (Ans.)

now,

→ Angle corresponding to ∠a = ∠q (d) (Ans.)

also,

→ (∠p + ∠q + ∠a + ∠z) / 6 = (180° + 180°)/6 = 360°/6 = 60° (a) (Ans.)

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