Question

one angle of a parralelogram is 100 degree. find the measure of other three angles​

Answer 1

Suppose=abcd is a parralelogram
Angle ABC=100
So,abc =cda(opposite angles of parralelogram are equal)
According to the theorem of transversal remaining 2 angles will be of 80 degree

Answer 2

Hey mate✌✌

LET THE ANGLES BE A,B ,C,D

LET THE ANGLES BE A,B ,C,DA=100°( given)

LET THE ANGLES BE A,B ,C,DA=100°( given)C=100°(opposite angles of parallelogram)

LET THE ANGLES BE A,B ,C,DA=100°( given)C=100°(opposite angles of parallelogram)A+B=180°{adjacent. angles}

LET THE ANGLES BE A,B ,C,DA=100°( given)C=100°(opposite angles of parallelogram)A+B=180°{adjacent. angles}100+B=180°,B=180-100

LET THE ANGLES BE A,B ,C,DA=100°( given)C=100°(opposite angles of parallelogram)A+B=180°{adjacent. angles}100+B=180°,B=180-100B=80°

LET THE ANGLES BE A,B ,C,DA=100°( given)C=100°(opposite angles of parallelogram)A+B=180°{adjacent. angles}100+B=180°,B=180-100B=80°Now,B =D=80°(opposite angles of parallelogram)

Therefore, A=C=100°,,,B=D=80°

THNXX AND MARK♥♥♥♥➡➡FØLLÖW...