one angle of a regular polygon is 168.how many sides does it have
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Answered by
40
QUESTION ---- one angle of a regular polygon is 168.how many sides does it have
ANSWER -----
FORMULA :
Each Interior Angle =
180 (n-2) / n. where n is no. of sides
Given Each interior angle = 168°
168 = 180n - 360 / n
168n = 180n - 360
180n - 168n = 360
12n = 360
n = 30
No. of sides = 30
>>>>>>>>>>>>>>>>>>>>
ANSWER = 30 sides
>>>>>>>>>>>>>>>>>>>>
ANSWER -----
FORMULA :
Each Interior Angle =
180 (n-2) / n. where n is no. of sides
Given Each interior angle = 168°
168 = 180n - 360 / n
168n = 180n - 360
180n - 168n = 360
12n = 360
n = 30
No. of sides = 30
>>>>>>>>>>>>>>>>>>>>
ANSWER = 30 sides
>>>>>>>>>>>>>>>>>>>>
Answered by
27
Answer:
360÷12°=30side
Explanation:
The only number that stays the same for the angles of all polygons is that the sum of the exterior angles is 360°.
If you know the size of an exterior angle(θ) in a regular polygon you can find the number of sides:
360°÷θ=number of sides
If you know the number of sides (n) you can find the size of each exterior angle of a regular polygon.
360÷n=θ
Interior angle 168°→
exterior angle=180°−168°=12°
360÷12°=30sides.
360÷12°=30side
Explanation:
The only number that stays the same for the angles of all polygons is that the sum of the exterior angles is 360°.
If you know the size of an exterior angle(θ) in a regular polygon you can find the number of sides:
360°÷θ=number of sides
If you know the number of sides (n) you can find the size of each exterior angle of a regular polygon.
360÷n=θ
Interior angle 168°→
exterior angle=180°−168°=12°
360÷12°=30sides.
Pranothi1:
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