Question

one angle of a triangle is 112 degre and the other two angles are equal. Find each angles ​

Answer 1

Given:

• One angle of a triangle is 112°
• Other two are equal.

Find:

• Each angles.

Diagram:

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Solution:

Let, the equal angles of traingle be x°

Now, we know that

➾ Sum of all angles of a triangle = 180°....[A.S.P]

➾ a + b + c = 180°

where,

• a = 112°
• b = x°
• c = x°

✱ Substituting these values ✱

➲ a + b + c = 180°

➲ 112° + x° + x° = 180°

➲ x° + x° = 180° - 112°

➲ x° + x° = 68°

➲ 2x° = 68°

➲ x° = 68/2

➲ x° = 34°

∴ Value of x = 34°

Hence,

❏ First angle = a = 112°

❏ Second angle = b = 34°

❏ Third angle = c = 34°

Answer 2

Given that -

✠ One angle of a triangle is 112°

✠ The other two angles are equal.

To find -

✠ Measure of each angles (3 angles)

Solution -

✠ Measure of ∠1st = 112°

✠ Measure of ∠2nd = 34°

✠ Measure of ∠3rd = 34°

Full solution -

~ Let us assume angles of triangle be a°

~ Now as already know that the sum of interior angles of triangle is 180° always. So, let's carry on

➙ 1st side + 2nd side + 3rd side = 180°

Here,

☃️ 1st side is 112°

☃️ 2nd side is a°

☃️ 3rd side is a°

➙ 112° + a° + a° = 180°

➙ 112° + 2a° = 180°

➙ 2a° = 180° - 112°

➙ 2a° = 68°

➙ a° = 68° / 2°

➙ a° = 34°

Henceforth, the value of a (2nd angle and 3rd angle) is 34°

So,

✠ Measure of ∠1st = 112°

✠ Measure of ∠2nd = 34°

✠ Measure of ∠3rd = 34°