one angle of a triangle is65 find the remaining two angles if their difference is 20
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one angle=47.5° and 2nd angle=67.5°
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given :-
one angle of a triangle = 65°
and the difference between the remaining two angles of the same triangle is 20.
let one of them be x. therefore the other one is x - 20°
we know that sum of all angles in a triangle is 180°
therefore 65° + x + x - 20° = 180°
=> 45° + 2x = 180°
=> 2x = 180° - 45°
=> 2x = 135°
=> x = 135/2
=> x = 77.5°
hence, the two angles are :-
x = 77.5° and x - 20 = 77.5° - 20° = 57.5°
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