One angle of parallelogram 24 less than twice the smallest adjacent angle. Find the each angle of parallelogram
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Answer:
Let the smallest angle be A is x degree.
Angle B is 2x-24 degree.
Opposite angles of parallelogram are equal,
Angle C = A = x degree
Angle D = 2x-24 degree
Since sum of all angles of parallelogram is 360 degree,
x+2x-24+x+2x-24=360
6x-48=360
6x=408
x=68 degree
A. 68 degree
B. 112 degree
C. 68 degree
D. 112 degree
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