Question

One bag contain 4 balls with numbers 2,4,5,7 and second bag contains 7 balls with numbers 1,2,3,4,5,6,7. If one of the two bags selected at random and then a ball is drawn. Find the probability that drawn ball bears the ood number

Answer 1

Answer:

The probability is 15/28.

Step-by-step explanation:

We use the following known formulas:

- P(A) = P(A ∩ B ) + P(A∩¬B).

- P(A∩B) = P(A) * P(B), where A and B are independent

P(Ball is Odd) = P(Ball is Odd in chosen bag AND We choose bag_1) + P(Ball is Odd in chosen bag AND We choose bag_2) = P(Ball is Odd in chosen bag) * P( We choose bag_1) + P(Ball is Odd in chosen bag) * P( We choose bag_2) = 2/4 * 1/2 + 4/7 * 1/2 = 15/14 * 1/2 = 15/28