One bag contains 4 white balls and 2 black balls; another contains 3 white balls and 5 black balls. If one ball is drawn from each bag, find the probability that (a) both are white (b) both are black (c) one is white and one is black.
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a.) no. of white ball =4
total number of balls in 1st bag ( white +black ball)=4+2=6
probability = total number of outcomes /total outcomes = 4/6 = 2/3 in
So, in 1st bag the probability for coming white ball is 2/3
in second bags same statement write but don't write the same value
probability =total number of outcomes /total outcomes =3/3+5=3/8
b.) no. of black ball in 1st bag =2
total number of balls (4+2)= 6
probability =total number of outcomes /total outcomes = 2/6 =1/3
in second bag write the same statement but don't write the same value
probability =total number of outcomes /total outcomes = 5/3 +5=5/8
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