one base angle of isosceles triangle is 65°.find its angle of vertex
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18
Answer:
since in an isosceles triangle the two sides are equal then
★the angles opposite to equal sides are equal.(angle A=B)
→angle A+B+C =180(angle sum property)
A+A+C=180
2A+C=180
2×65+C =180
C=180-130
C=50°
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Vertex angle is 50° if one base angle of isosceles triangle is 65°
Given:
One base angle of isosceles triangle is 65°
To Find:
Vertex angle
Solution:
Isosceles triangle have 2 Equal sides.
Angles opposite to equal sides are equal in measure.
Both Base angles of an isosceles triangle are of Equal measure
one base angle = 65°
=> Another base angle = 65°
Assume that Vertex angle = x°
Sum of all the angles of a triangle is 180°
=> 65° + 65° + x° = 180°
=> 130° + x° = 180°
=> x° = 50°
Vertex angle = 50°
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