One big and small big piece of cork are pushed below the surface of water which rise swiftly
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i belive it wood be the the small on ok so > The small one
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HLW FRIEND
THE CORK WHICH WILL BE HAVING SMALLER SURFACE AREA WILL MOVE MUCH FASTER THAN THE ANOTHER ONE , IF U APPLIED EQUAL FORCES ON BOTH THE CORK
Because UPTHRUST/PRESSURE=FORCE/AREA
SO SMALLER THE AREA MORE WILL BE UPTHRUST AND SO MORE WILL BE SPEED IN MOVING IN UPWARD DIRECTION
THANK YOU☺
THE CORK WHICH WILL BE HAVING SMALLER SURFACE AREA WILL MOVE MUCH FASTER THAN THE ANOTHER ONE , IF U APPLIED EQUAL FORCES ON BOTH THE CORK
Because UPTHRUST/PRESSURE=FORCE/AREA
SO SMALLER THE AREA MORE WILL BE UPTHRUST AND SO MORE WILL BE SPEED IN MOVING IN UPWARD DIRECTION
THANK YOU☺
pppratikpoudel:
But upthrust = VDG , d and g are same for both and V is greater for big cork so why not big one rise swiftly
Bro according to my answer and with given reason i m correct!
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