one body have ten Columb charge other have -15 coulmb charge distance between is 1 meter what will be ratio of force experienced by each other
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There are two electric charges q1 = 10 C and q2 = -15 C, separated by a distance of 1m.
There is a Coulomb's force of attraction between them.
F = 1/(4πε) * q1 * q2 / d²
According to Newton's third law, in the isolated system of electric charges, the net force on the system is zero. Also, the force exerted by q1 on q2 is equal to the force exerted by q2 on q1. But the forces are in opposite directions.
So the ratio will be equal to -1 (or 1 if only magnitudes are taken into account).
There is a Coulomb's force of attraction between them.
F = 1/(4πε) * q1 * q2 / d²
According to Newton's third law, in the isolated system of electric charges, the net force on the system is zero. Also, the force exerted by q1 on q2 is equal to the force exerted by q2 on q1. But the forces are in opposite directions.
So the ratio will be equal to -1 (or 1 if only magnitudes are taken into account).
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