One card is drawn at random from a pack of card. Of getting a diamond card
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1/4
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1
one card is drawn at random from pack of 52 cards
n(s)=52
Let A be the event of getting a diamond
A={13}
n(A)=13
P(A)= n(A)/n(s)
=13/52
=1/4
Therefore probability of getting a diamond card is 1/4
n(s)=52
Let A be the event of getting a diamond
A={13}
n(A)=13
P(A)= n(A)/n(s)
=13/52
=1/4
Therefore probability of getting a diamond card is 1/4
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