Math, asked by Anonymous, 7 months ago

One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting

(i) a king of red colour

(ii) a face card

(iii) a red face card

(iv) the jack of hearts

(v) a spade

(vi) the queen of diamonds​

Answers

Answered by MrDRUG
0

Given :-

One card is drawn from a well-shuffled deck of 52 cards

Total number of possible outcomes = 52

To find :-

the probability of getting

(i) a king of red colour

(ii) a face card

(iii) a red face card

(iv) the jack of hearts

(v) a spade

(vi) the queen of diamonds

Formulae :-

P(E) =  \frac{Number  \: of  \: favourable \:  outcomes}{Total \:  number  \: of  \: outcomes}

Solution :-

(i) Total numbers of king of red colour = 2

P (getting  \: a  \: king \:  of  \: red  \: colour) = \frac{2}{52}  = >  \frac{1}{26}

(ii) Total numbers of face cards = 12

P (getting a face card) =  \frac{12}{52}  =  \frac{3}{13}

(iii) Total numbers of red face cards = 6

P (getting \:  a  \: king \:  of \:  red  \: colour) =  \frac{6}{52}  = \frac{3}{26}

(iv) Total numbers of jack of hearts = 1

P (getting \:  a \:  king  \: of \:  red  \: colour) =  \frac{1}{52}

(v) Total numbers of king of spade = 13

P (getting \:  a  \: king \:  of \:  red  \: colour) =  \frac{13}{52}  = \frac{1}{4}

(vi) Total numbers of queen of diamonds = 1

P (getting \:  a  \: king \:  of  \: red  \: colour) =  \frac{1}{52}

Answered by srikanthn711
12

SOLUTION :-

(i) Total numbers of king of red colour = 2

P (getting  \: a  \: king \:  of  \: red  \: colour) = \frac{2}{52}  = >  \frac{1}{26}

(ii) Total numbers of face cards = 12

P (getting a face card) =  \frac{12}{52}  =  \frac{3}{13}

(iii) Total numbers of red face cards = 6

P (getting \:  a  \: king \:  of \:  red  \: colour) =  \frac{6}{52}  = \frac{3}{26}

(iv) Total numbers of jack of hearts = 1

P (getting \:  a \:  king  \: of \:  red  \: colour) =  \frac{1}{52}

(v) Total numbers of king of spade = 13

P (getting \:  a  \: king \:  of \:  red  \: colour) =  \frac{13}{52}  = \frac{1}{4}

(vi) Total numbers of queen of diamonds = 1

P (getting \:  a  \: king \:  of  \: red  \: colour) =  \frac{1}{52}

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