Question

One compound contain 4.07% Hydrogen, 24.47% carbon and 71.65% chlorine. Its molar mass is

98.96 g. Find empirical formula and molecular formula.​

Answer 1

Explanation:

• Divide the given percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

divide all values with the lowest value obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical formula is

CH 2Cl

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C 2 H 4Cl 2 .