Question

one convex quadrilaterals two angle is square angles and another angles measurements is al 120° , now answered the number of polygon sides.



plz answer my questions step by step don't answer directly.
plz answer my questions first.​

Answer 1

• Let the number of side of polygon be = n

Since

• two angles are right angles , therefore number of each angle of 120° = (n-2)

So,

• sum of interior angle is = [2×90+(n-2)×120]

Also,

sum of interior angle of polygon of n side = [2n-4×90°]

Now,

→ [2×90+(n-2)×120] = (2n-4)×90

→ 180+(n-2)×120 = (2n-4)×90

→ 60+(n-2)×40 = (2n+4)×30

• Now, divide by 3

→ 60+40n-80=60n-120

→ -20+120=60n-40n

→ 100= 20n

→ 100/20=n

→ n=5

Hence,

The polygon have 5 sides

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